Optimal. Leaf size=198 \[ -\frac{33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x)^2}-\frac{231 e^3 (d+e x)^{5/2}}{64 b^4 (a+b x)}+\frac{1155 e^4 \sqrt{d+e x} (b d-a e)}{64 b^6}-\frac{1155 e^4 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{64 b^{13/2}}-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{385 e^4 (d+e x)^{3/2}}{64 b^5} \]
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Rubi [A] time = 0.122621, antiderivative size = 198, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 5, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.152, Rules used = {27, 47, 50, 63, 208} \[ -\frac{33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x)^2}-\frac{231 e^3 (d+e x)^{5/2}}{64 b^4 (a+b x)}+\frac{1155 e^4 \sqrt{d+e x} (b d-a e)}{64 b^6}-\frac{1155 e^4 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{64 b^{13/2}}-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{385 e^4 (d+e x)^{3/2}}{64 b^5} \]
Antiderivative was successfully verified.
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Rule 27
Rule 47
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(a+b x) (d+e x)^{11/2}}{\left (a^2+2 a b x+b^2 x^2\right )^3} \, dx &=\int \frac{(d+e x)^{11/2}}{(a+b x)^5} \, dx\\ &=-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{(11 e) \int \frac{(d+e x)^{9/2}}{(a+b x)^4} \, dx}{8 b}\\ &=-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{\left (33 e^2\right ) \int \frac{(d+e x)^{7/2}}{(a+b x)^3} \, dx}{16 b^2}\\ &=-\frac{33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x)^2}-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{\left (231 e^3\right ) \int \frac{(d+e x)^{5/2}}{(a+b x)^2} \, dx}{64 b^3}\\ &=-\frac{231 e^3 (d+e x)^{5/2}}{64 b^4 (a+b x)}-\frac{33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x)^2}-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{\left (1155 e^4\right ) \int \frac{(d+e x)^{3/2}}{a+b x} \, dx}{128 b^4}\\ &=\frac{385 e^4 (d+e x)^{3/2}}{64 b^5}-\frac{231 e^3 (d+e x)^{5/2}}{64 b^4 (a+b x)}-\frac{33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x)^2}-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{\left (1155 e^4 (b d-a e)\right ) \int \frac{\sqrt{d+e x}}{a+b x} \, dx}{128 b^5}\\ &=\frac{1155 e^4 (b d-a e) \sqrt{d+e x}}{64 b^6}+\frac{385 e^4 (d+e x)^{3/2}}{64 b^5}-\frac{231 e^3 (d+e x)^{5/2}}{64 b^4 (a+b x)}-\frac{33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x)^2}-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{\left (1155 e^4 (b d-a e)^2\right ) \int \frac{1}{(a+b x) \sqrt{d+e x}} \, dx}{128 b^6}\\ &=\frac{1155 e^4 (b d-a e) \sqrt{d+e x}}{64 b^6}+\frac{385 e^4 (d+e x)^{3/2}}{64 b^5}-\frac{231 e^3 (d+e x)^{5/2}}{64 b^4 (a+b x)}-\frac{33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x)^2}-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}+\frac{\left (1155 e^3 (b d-a e)^2\right ) \operatorname{Subst}\left (\int \frac{1}{a-\frac{b d}{e}+\frac{b x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{64 b^6}\\ &=\frac{1155 e^4 (b d-a e) \sqrt{d+e x}}{64 b^6}+\frac{385 e^4 (d+e x)^{3/2}}{64 b^5}-\frac{231 e^3 (d+e x)^{5/2}}{64 b^4 (a+b x)}-\frac{33 e^2 (d+e x)^{7/2}}{32 b^3 (a+b x)^2}-\frac{11 e (d+e x)^{9/2}}{24 b^2 (a+b x)^3}-\frac{(d+e x)^{11/2}}{4 b (a+b x)^4}-\frac{1155 e^4 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{64 b^{13/2}}\\ \end{align*}
Mathematica [C] time = 0.0268202, size = 52, normalized size = 0.26 \[ \frac{2 e^4 (d+e x)^{13/2} \, _2F_1\left (5,\frac{13}{2};\frac{15}{2};-\frac{b (d+e x)}{a e-b d}\right )}{13 (a e-b d)^5} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.02, size = 701, normalized size = 3.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.14531, size = 2079, normalized size = 10.5 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.25404, size = 643, normalized size = 3.25 \begin{align*} \frac{1155 \,{\left (b^{2} d^{2} e^{4} - 2 \, a b d e^{5} + a^{2} e^{6}\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{64 \, \sqrt{-b^{2} d + a b e} b^{6}} - \frac{2295 \,{\left (x e + d\right )}^{\frac{7}{2}} b^{5} d^{2} e^{4} - 5855 \,{\left (x e + d\right )}^{\frac{5}{2}} b^{5} d^{3} e^{4} + 5153 \,{\left (x e + d\right )}^{\frac{3}{2}} b^{5} d^{4} e^{4} - 1545 \, \sqrt{x e + d} b^{5} d^{5} e^{4} - 4590 \,{\left (x e + d\right )}^{\frac{7}{2}} a b^{4} d e^{5} + 17565 \,{\left (x e + d\right )}^{\frac{5}{2}} a b^{4} d^{2} e^{5} - 20612 \,{\left (x e + d\right )}^{\frac{3}{2}} a b^{4} d^{3} e^{5} + 7725 \, \sqrt{x e + d} a b^{4} d^{4} e^{5} + 2295 \,{\left (x e + d\right )}^{\frac{7}{2}} a^{2} b^{3} e^{6} - 17565 \,{\left (x e + d\right )}^{\frac{5}{2}} a^{2} b^{3} d e^{6} + 30918 \,{\left (x e + d\right )}^{\frac{3}{2}} a^{2} b^{3} d^{2} e^{6} - 15450 \, \sqrt{x e + d} a^{2} b^{3} d^{3} e^{6} + 5855 \,{\left (x e + d\right )}^{\frac{5}{2}} a^{3} b^{2} e^{7} - 20612 \,{\left (x e + d\right )}^{\frac{3}{2}} a^{3} b^{2} d e^{7} + 15450 \, \sqrt{x e + d} a^{3} b^{2} d^{2} e^{7} + 5153 \,{\left (x e + d\right )}^{\frac{3}{2}} a^{4} b e^{8} - 7725 \, \sqrt{x e + d} a^{4} b d e^{8} + 1545 \, \sqrt{x e + d} a^{5} e^{9}}{192 \,{\left ({\left (x e + d\right )} b - b d + a e\right )}^{4} b^{6}} + \frac{2 \,{\left ({\left (x e + d\right )}^{\frac{3}{2}} b^{10} e^{4} + 15 \, \sqrt{x e + d} b^{10} d e^{4} - 15 \, \sqrt{x e + d} a b^{9} e^{5}\right )}}{3 \, b^{15}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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